What is (-2g^2h)^3(g/(4h^2))^2 ?

The solution to (-2g^2h)^3(g/(4h^2))^2 is -(g^8)/(2h)

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simplify (-2g^2h)^3(g/(4h^2))^2

simplify

(- 2 g^{2} h)^{3} (\frac{g}{4 h ^{2}})^{2}

- \frac{g ^{8}}{2 h}

Solution steps

(- 2 g^{2} h)^{3} (\frac{g}{4 h ^{2}})^{2}

Simplify

(- 2 g^{2} h)^{3} : - 8 g^{6} h^{3}

= - 8 g^{6} h^{3} (\frac{g}{4 h ^{2}})^{2}

Simplify

(\frac{g}{4 h ^{2}})^{2} : \frac{g ^{2}}{16 h ^{4}}

= - 8 g^{6} h^{3} \frac{g ^{2}}{16 h ^{4}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{8 g ^{6} h ^{3} g ^{2}}{16 h ^{4}}

Factor the number:

16 = 8 \cdot 2

= - \frac{8 g ^{6} h ^{3} g ^{2}}{8 \cdot 2 h ^{4}}

Cancel the common factor:

8

= - \frac{g ^{6} h ^{3} g ^{2}}{2 h ^{4}}

Simplify

\frac{h ^{3}}{h ^{4}} : \frac{1}{h}

= - \frac{g ^{6} g ^{2}}{2 h}

Simplify

g^{6} g^{2} : g^{8}

= - \frac{g ^{8}}{2 h}

5 n^{2} = 9 n

\frac{1}{n ^{7} \cdot n ^{- 5}}

- \frac{6}{6}

\frac{3}{2} - \frac{2}{3}

2 (x + 3) \geq 4 (x - 1)

What is (-2g^2h)^3(g/(4h^2))^2 ?
The solution to (-2g^2h)^3(g/(4h^2))^2 is -(g^8)/(2h)