What is 2/((s+2)^2+4)+1/(s+2) ?

The solution to 2/((s+2)^2+4)+1/(s+2) is 2/(s^2+4s+8)+1/(s+2)

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simplify 2/((s+2)^2+4)+1/(s+2)

simplify

\frac{2}{( s + 2 ) ^{2} + 4} + \frac{1}{s + 2}

\frac{2}{s ^{2} + 4 s + 8} + \frac{1}{s + 2}

Solution steps

\frac{2}{( s + 2 ) ^{2} + 4} + \frac{1}{s + 2}

Expand

(s + 2)^{2} : s^{2} + 4 s + 4

= \frac{2}{s ^{2} + 4 s + 4 + 4} + \frac{1}{s + 2}

Add the numbers:

4 + 4 = 8

= \frac{2}{s ^{2} + 4 s + 8} + \frac{1}{s + 2}

\frac{x ^{3} - 6 x ^{2}}{x ^{2} + 2 x - 48}

(x + 8) (3 x + 3)

10 5^{2}

(3 x + 4) (2 x + 3)

- 5 - 0

What is 2/((s+2)^2+4)+1/(s+2) ?
The solution to 2/((s+2)^2+4)+1/(s+2) is 2/(s^2+4s+8)+1/(s+2)