What is (-10-i)/(-9-6i) ?

The solution to (-10-i)/(-9-6i) is 32/39-17/39 i

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simplify (-10-i)/(-9-6i)

simplify

\frac{- 10 - i}{- 9 - 6 i}

\frac{32}{39} - \frac{17}{39} i

Solution steps

\frac{- 10 - i}{- 9 - 6 i}

Multiply by the conjugate

\frac{- 9 + 6 i}{- 9 + 6 i}

= \frac{( - 10 - i ) ( - 9 + 6 i )}{( - 9 - 6 i ) ( - 9 + 6 i )}

Simplify

\frac{( - 10 - i ) ( - 9 + 6 i )}{( - 9 - 6 i ) ( - 9 + 6 i )} : \frac{96 - 51 i}{117}

= \frac{96 - 51 i}{117}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{96}{117} + \frac{- 51}{117} i

Simplify

\frac{96}{117} + \frac{- 51}{117} i : \frac{32}{39} - \frac{17}{39} i

= \frac{32}{39} - \frac{17}{39} i

cos (θ) cos (θ)

(2 x - 1) (x^{2} - 10 x + 8)

\frac{2 + 14 i}{9 + 14 i}

\frac{20}{80}

(- 1 + h)^{2}