What is (6b^3+6-b^4)-(8b^3-6b^4+2) ?

The solution to (6b^3+6-b^4)-(8b^3-6b^4+2) is 5b^4-2b^3+4

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simplify (6b^3+6-b^4)-(8b^3-6b^4+2)

simplify

(6 b^{3} + 6 - b^{4}) - (8 b^{3} - 6 b^{4} + 2)

5 b^{4} - 2 b^{3} + 4

Solution steps

(6 b^{3} + 6 - b^{4}) - (8 b^{3} - 6 b^{4} + 2)

Apply rule:

(a) = a

(6 b^{3} + 6 - b^{4}) = 6 b^{3} + 6 - b^{4}

= 6 b^{3} + 6 - b^{4} - (8 b^{3} - 6 b^{4} + 2)

Apply the distributive law:

- (a - b) = - a + b

- (8 b^{3} - 6 b^{4} + 2) = - 8 b^{3} + 6 b^{4} - 2

= 6 b^{3} + 6 - b^{4} - 8 b^{3} + 6 b^{4} - 2

Group like terms

= - b^{4} + 6 b^{4} + 6 b^{3} - 8 b^{3} + 6 - 2

Add similar elements:

- b^{4} + 6 b^{4} = 5 b^{4}

= 5 b^{4} + 6 b^{3} - 8 b^{3} + 6 - 2

Add similar elements:

6 b^{3} - 8 b^{3} = - 2 b^{3}

= 5 b^{4} - 2 b^{3} + 6 - 2

Subtract the numbers:

6 - 2 = 4

= 5 b^{4} - 2 b^{3} + 4

\frac{3}{x} + \frac{5}{x - 1}

6 \cdot 14

3 (2 x^{2} - 1)

(x^{4} - 1)^{2}

\frac{3 b - 5}{b ^{2}} \cdot \frac{b ^{4}}{5 - 3 b}

What is (6b^3+6-b^4)-(8b^3-6b^4+2) ?
The solution to (6b^3+6-b^4)-(8b^3-6b^4+2) is 5b^4-2b^3+4