What are the solutions to the equation -p^2=99 ?

The solutions to the equation -p^2=99 are p=3sqrt(11)i,p=-3sqrt(11)i

Find the zeros of -p^2=99

The zeros of -p^2=99 are p=3sqrt(11)i,p=-3sqrt(11)i

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- p^{2} = 99

p = 311 i, p = - 311 i

Solution steps

- p^{2} = 99

Divide both sides by

- 1

p^{2} = - 99

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - 99, p = - - 99

- 99 = 311 i

- - 99 = - 311 i

p = 311 i, p = - 311 i

(\frac{2}{x + 1})^{2}

3 x^{2} - 27 x = 0

∣ 3 x - 1 ∣ < 2

\frac{112 a ^{3} b ^{2}}{8 ab}

- 2 (8 - 3 x) \geq 6 x + 2

What are the solutions to the equation -p^2=99 ?
The solutions to the equation -p^2=99 are p=3sqrt(11)i,p=-3sqrt(11)i
Find the zeros of -p^2=99
The zeros of -p^2=99 are p=3sqrt(11)i,p=-3sqrt(11)i