What is expand (2x+1)(x^2-4x+8) ?

The solution to expand (2x+1)(x^2-4x+8) is 2x^3-7x^2+12x+8

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expand (2x+1)(x^2-4x+8)

expand

(2 x + 1) (x^{2} - 4 x + 8)

2 x^{3} - 7 x^{2} + 12 x + 8

Solution steps

(2 x + 1) (x^{2} - 4 x + 8)

Distribute parentheses

= 2 x x^{2} + 2 x (- 4 x) + 2 x \cdot 8 + 1 \cdot x^{2} + 1 \cdot (- 4 x) + 1 \cdot 8

Simplify

2 x x^{2} + 2 x (- 4 x) + 2 x \cdot 8 + 1 \cdot x^{2} + 1 \cdot (- 4 x) + 1 \cdot 8 : 2 x^{3} - 7 x^{2} + 12 x + 8

= 2 x^{3} - 7 x^{2} + 12 x + 8

\frac{- 3 - 9 i}{- 1 + 10 i}

\frac{4 !}{( 4 - 4 ) !}

\frac{- 21 - 15 i}{- 1 - 6 i}

(2 x + 9)^{2}

- 7 + (- 3)

What is expand (2x+1)(x^2-4x+8) ?
The solution to expand (2x+1)(x^2-4x+8) is 2x^3-7x^2+12x+8