What is expand mn^4(m^3-2m^2n+4mn^2-n^2+4) ?

The solution to expand mn^4(m^3-2m^2n+4mn^2-n^2+4) is m^4n^4-2m^3n^5+4m^2n^6-mn^6+4mn^4

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expand mn^4(m^3-2m^2n+4mn^2-n^2+4)

expand

m n^{4} (m^{3} - 2 m^{2} n + 4 m n^{2} - n^{2} + 4)

m^{4} n^{4} - 2 m^{3} n^{5} + 4 m^{2} n^{6} - m n^{6} + 4 m n^{4}

Solution steps

m n^{4} (m^{3} - 2 m^{2} n + 4 m n^{2} - n^{2} + 4)

Distribute parentheses

= m n^{4} m^{3} + m n^{4} (- 2 m^{2} n) + m n^{4} \cdot 4 m n^{2} + m n^{4} (- n^{2}) + m n^{4} \cdot 4

Simplify

m n^{4} m^{3} + m n^{4} (- 2 m^{2} n) + m n^{4} \cdot 4 m n^{2} + m n^{4} (- n^{2}) + m n^{4} \cdot 4 : m^{4} n^{4} - 2 m^{3} n^{5} + 4 m^{2} n^{6} - m n^{6} + 4 m n^{4}

= m^{4} n^{4} - 2 m^{3} n^{5} + 4 m^{2} n^{6} - m n^{6} + 4 m n^{4}

x + 3 + \frac{3 x}{x + 5}

- 9 + - 28

(\frac{1}{e})^{2} - 2 ln (\frac{1}{e})

- 6 a + 7 (- 2 a - 4)

27 a

What is expand mn^4(m^3-2m^2n+4mn^2-n^2+4) ?
The solution to expand mn^4(m^3-2m^2n+4mn^2-n^2+4) is m^4n^4-2m^3n^5+4m^2n^6-mn^6+4mn^4