What is factor 4x^4-8x^3+12x^2 ?

The solution to factor 4x^4-8x^3+12x^2 is 4x^2(x^2-2x+3)

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factor 4x^4-8x^3+12x^2

factor

4 x^{4} - 8 x^{3} + 12 x^{2}

4 x^{2} (x^{2} - 2 x + 3)

Solution steps

4 x^{4} - 8 x^{3} + 12 x^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} = x x^{2}

= 4 x^{2} x^{2} - 8 x x^{2} + 12 x^{2}

Rewrite

8

4 \cdot 2

Rewrite

12

4 \cdot 3

= 4 x^{2} x^{2} - 4 \cdot 2 x x^{2} + 4 \cdot 3 x^{2}

Factor out common term

4 x^{2}

= 4 x^{2} (x^{2} - 2 x + 3)

32 x^{2}

\frac{40}{52}

(x - 2) (2 x^{2} - 5 x - 9)

\frac{14}{100}

(2 x - 3) (x - 1)

What is factor 4x^4-8x^3+12x^2 ?
The solution to factor 4x^4-8x^3+12x^2 is 4x^2(x^2-2x+3)