What is (\frac{3x)/(x^2+10x+24)}{(x-6)/(x^2-36)} ?

The solution to (\frac{3x)/(x^2+10x+24)}{(x-6)/(x^2-36)} is (3x)/(x+4)

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simplify (\frac{3x)/(x^2+10x+24)}{(x-6)/(x^2-36)}

simplify

\frac{\frac{3 x}{x ^{2} + 10 x + 24}}{\frac{x - 6}{x ^{2} - 36}}

\frac{3 x}{x + 4}

Solution steps

\frac{\frac{3 x}{x ^{2} + 10 x + 24}}{\frac{x - 6}{x ^{2} - 36}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{3 x ( x ^{2} - 36 )}{( x ^{2} + 10 x + 24 ) ( x - 6 )}

Cancel

\frac{3 x ( x ^{2} - 36 )}{( x ^{2} + 10 x + 24 ) ( x - 6 )} : \frac{3 x}{x + 4}

= \frac{3 x}{x + 4}

11 r - 12 r

ln (0 + 1)

- 23 \cdot - 46

(x - 1) (x^{2} - 5 x + 6)

- 6 + (- 6)

What is (\frac{3x)/(x^2+10x+24)}{(x-6)/(x^2-36)} ?
The solution to (\frac{3x)/(x^2+10x+24)}{(x-6)/(x^2-36)} is (3x)/(x+4)