What is (3v^2-7v-10)(v-4)^{-1} ?

The solution to (3v^2-7v-10)(v-4)^{-1} is (3v^2-7v-10)/(v-4)

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simplify (3v^2-7v-10)(v-4)^{-1}

simplify

(3 v^{2} - 7 v - 10) (v - 4)^{- 1}

\frac{3 v ^{2} - 7 v - 10}{v - 4}

Solution steps

(3 v^{2} - 7 v - 10) (v - 4)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(v - 4)^{- 1} = \frac{1}{v - 4}

= (3 v^{2} - 7 v - 10) \frac{1}{v - 4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 v ^{2} - 7 v - 10 ) \cdot 1}{v - 4}

Apply rule:

a \cdot 1 = a

(3 v^{2} - 7 v - 10) \cdot 1 = (3 v^{2} - 7 v - 10)

= \frac{3 v ^{2} - 7 v - 10}{v - 4}

\frac{1543.65}{( - 4 )}

- 9 - (- 2)

(2 a + 3)^{3}

(23 + 5 - 52) \cdot 42

(6 x + 4)^{2}

What is (3v^2-7v-10)(v-4)^{-1} ?
The solution to (3v^2-7v-10)(v-4)^{-1} is (3v^2-7v-10)/(v-4)