What is (3x-1)/(3x)+(x+1)/(x^2)-(2x+1)/(2x) ?

The solution to (3x-1)/(3x)+(x+1)/(x^2)-(2x+1)/(2x) is -5/(6x)+(x+1)/(x^2)

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simplify (3x-1)/(3x)+(x+1)/(x^2)-(2x+1)/(2x)

simplify

\frac{3 x - 1}{3 x} + \frac{x + 1}{x ^{2}} - \frac{2 x + 1}{2 x}

- \frac{5}{6 x} + \frac{x + 1}{x ^{2}}

Solution steps

\frac{3 x - 1}{3 x} + \frac{x + 1}{x ^{2}} - \frac{2 x + 1}{2 x}

Join

\frac{3 x - 1}{3 x} - \frac{2 x + 1}{2 x} : - \frac{5}{6 x}

= - \frac{5}{6 x} + \frac{x + 1}{x ^{2}}

\frac{1}{2} - (\frac{2}{3})^{2}

(x - 1.5)^{2}

(x - 1) (x + 3) (x - 4)

\frac{- 1 - 9 i}{- 2 - 9 i}

- \frac{5}{1}

What is (3x-1)/(3x)+(x+1)/(x^2)-(2x+1)/(2x) ?
The solution to (3x-1)/(3x)+(x+1)/(x^2)-(2x+1)/(2x) is -5/(6x)+(x+1)/(x^2)