What is (x^2+5x)/(x^2-25)*(8x-40)/(4x) ?

The solution to (x^2+5x)/(x^2-25)*(8x-40)/(4x) is 2

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simplify (x^2+5x)/(x^2-25)*(8x-40)/(4x)

simplify

\frac{x ^{2} + 5 x}{x ^{2} - 25} \cdot \frac{8 x - 40}{4 x}

2

Solution steps

\frac{x ^{2} + 5 x}{x ^{2} - 25} \cdot \frac{8 x - 40}{4 x}

Cancel

\frac{x ^{2} + 5 x}{x ^{2} - 25} : \frac{x}{x - 5}

= \frac{x}{x - 5} \cdot \frac{8 x - 40}{4 x}

Cancel

\frac{8 x - 40}{4 x} : \frac{2 ( x - 5 )}{x}

= \frac{x}{x - 5} \cdot \frac{2 ( x - 5 )}{x}

Cross-cancel common factor:

x

= \frac{2 ( x - 5 )}{x - 5}

Cancel the common factor:

x - 5

= 2

(2 x + 9) (3 x - 5)

7 x^{0}

\frac{52 x ^{6}}{13 x ^{- 7}}

- 4 + (- 9)

20 lo g_{10} (0.5)

What is (x^2+5x)/(x^2-25)*(8x-40)/(4x) ?
The solution to (x^2+5x)/(x^2-25)*(8x-40)/(4x) is 2