What is (e^x+e^{-x})/(e^x-e^{-x)} ?

The solution to (e^x+e^{-x})/(e^x-e^{-x)} is (e^{2x}+1)/(e^{2x)-1}

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simplify (e^x+e^{-x})/(e^x-e^{-x)}

simplify

\frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}}

\frac{e ^{2 x} + 1}{e ^{2 x} - 1}

Solution steps

\frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}}

Factor

e^{x} + e^{- x} : e^{- x} (e^{2 x} + 1)

= \frac{e ^{- x} ( e ^{2 x} + 1 )}{e ^{x} - e ^{- x}}

Factor

e^{x} - e^{- x} : e^{- x} (e^{2 x} - 1)

= \frac{e ^{- x} ( e ^{2 x} + 1 )}{e ^{- x} ( e ^{2 x} - 1 )}

Cancel the common factor:

e^{- x}

= \frac{e ^{2 x} + 1}{e ^{2 x} - 1}

\frac{125}{6}

3^{x} + 3^{x}

(x^{2} + 3)^{2} + 3

g (- 1)

5 a^{2} - 15 ab - 10 a c

What is (e^x+e^{-x})/(e^x-e^{-x)} ?
The solution to (e^x+e^{-x})/(e^x-e^{-x)} is (e^{2x}+1)/(e^{2x)-1}