What are the solutions to the equation 2a^2=-6+8a ?

The solutions to the equation 2a^2=-6+8a are a=3,a=1

Find the zeros of 2a^2=-6+8a

The zeros of 2a^2=-6+8a are a=3,a=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 a^{2} = - 6 + 8 a

a = 3, a = 1

Solution steps

2 a^{2} = - 6 + 8 a

Move

8 a

to the left side

2 a^{2} - 8 a = - 6

Move

6

to the left side

2 a^{2} - 8 a + 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 6 = 4

a_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 2}, a_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 2}

a = \frac{- ( - 8 ) + 4}{2 \cdot 2} : 3

a = \frac{- ( - 8 ) - 4}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

a = 3, a = 1

4 m = 2 (m - 4)

3 (- 8 x - 4) + 15 \geq - 15 x + 12 or 4 x + 5 > 2 x - 11

1 - 9 x = - 62

9 - ∣ 2 x - 3 ∣ \geq 5

a + \frac{1}{2} a + \frac{2}{3} a

What are the solutions to the equation 2a^2=-6+8a ?
The solutions to the equation 2a^2=-6+8a are a=3,a=1
Find the zeros of 2a^2=-6+8a
The zeros of 2a^2=-6+8a are a=3,a=1