What is (x^4+4x^3)/(x^2+3x-4) ?

The solution to (x^4+4x^3)/(x^2+3x-4) is (x^3)/(x-1)

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simplify (x^4+4x^3)/(x^2+3x-4)

simplify

\frac{x ^{4} + 4 x ^{3}}{x ^{2} + 3 x - 4}

\frac{x ^{3}}{x - 1}

Solution steps

\frac{x ^{4} + 4 x ^{3}}{x ^{2} + 3 x - 4}

Factor

x^{4} + 4 x^{3} : x^{3} (x + 4)

= \frac{x ^{3} ( x + 4 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{x ^{3} ( x + 4 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x ^{3}}{x - 1}

\frac{x ^{3} + 4 x ^{2} - 21 x}{x ^{3} - 9 x}

(z + 1)^{2}

\frac{x - 2}{4 x} + \frac{x + 5}{10 x}

- 8 x - 11 x

lo g_{10} (\frac{5}{4})

What is (x^4+4x^3)/(x^2+3x-4) ?
The solution to (x^4+4x^3)/(x^2+3x-4) is (x^3)/(x-1)