What is factor x^4-2x^3-7x^2+8x+12 ?

The solution to factor x^4-2x^3-7x^2+8x+12 is (x+1)(x-3)(x+2)(x-2)

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factor x^4-2x^3-7x^2+8x+12

factor

x^{4} - 2 x^{3} - 7 x^{2} + 8 x + 12

(x + 1) (x - 3) (x + 2) (x - 2)

Solution steps

x^{4} - 2 x^{3} - 7 x^{2} + 8 x + 12

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 2 x ^{3} - 7 x ^{2} + 8 x + 12}{x + 1}

\frac{x ^{4} - 2 x ^{3} - 7 x ^{2} + 8 x + 12}{x + 1} = x^{3} - 3 x^{2} - 4 x + 12

= (x + 1) (x^{3} - 3 x^{2} - 4 x + 12)

Factor

x^{3} - 3 x^{2} - 4 x + 12 : (x - 3) (x + 2) (x - 2)

= (x + 1) (x - 3) (x + 2) (x - 2)

lo g_{4} (\frac{1}{8})

\frac{2}{( s - 2 ) ^{2} + 4} - \frac{1}{s - 2}

\frac{5 x ^{4} y ^{5}}{- 6 x ^{4} y}

\frac{1}{4} \cdot (- 4)

\frac{x}{3} + \frac{x}{2}

What is factor x^4-2x^3-7x^2+8x+12 ?
The solution to factor x^4-2x^3-7x^2+8x+12 is (x+1)(x-3)(x+2)(x-2)