What is expand (4x-5)(2x^2-3x-3) ?

The solution to expand (4x-5)(2x^2-3x-3) is 8x^3-22x^2+3x+15

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expand (4x-5)(2x^2-3x-3)

expand

(4 x - 5) (2 x^{2} - 3 x - 3)

8 x^{3} - 22 x^{2} + 3 x + 15

Solution steps

(4 x - 5) (2 x^{2} - 3 x - 3)

Distribute parentheses

= 4 x \cdot 2 x^{2} + 4 x (- 3 x) + 4 x (- 3) - 5 \cdot 2 x^{2} - 5 (- 3 x) - 5 (- 3)

Simplify

4 x \cdot 2 x^{2} + 4 x (- 3 x) + 4 x (- 3) - 5 \cdot 2 x^{2} - 5 (- 3 x) - 5 (- 3) : 8 x^{3} - 22 x^{2} + 3 x + 15

= 8 x^{3} - 22 x^{2} + 3 x + 15

y - (- 3 y)

\frac{40}{7}

\frac{18 x ^{2} - 162 x}{9 x}

\frac{\frac{2}{x} + 3}{\frac{4}{x ^{2}} - 9}

(4 x^{2} + x) - (x^{2} + 2 x)

What is expand (4x-5)(2x^2-3x-3) ?
The solution to expand (4x-5)(2x^2-3x-3) is 8x^3-22x^2+3x+15