What are the solutions to the equation 3x^2+12x-63=0 ?

The solutions to the equation 3x^2+12x-63=0 are x=3,x=-7

Find the zeros of 3x^2+12x-63=0

The zeros of 3x^2+12x-63=0 are x=3,x=-7

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3 x^{2} + 12 x - 63 = 0

x = 3, x = - 7

Solution steps

3 x^{2} + 12 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 63 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 63) = 30

x_{1, 2} = \frac{- 12 \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 30}{2 \cdot 3}, x_{2} = \frac{- 12 - 30}{2 \cdot 3}

x = \frac{- 12 + 30}{2 \cdot 3} : 3

x = \frac{- 12 - 30}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

3 x - 6 \geq - 24

(- 3)^{5}

\frac{1 + 5 i}{5 - i}

- \frac{3}{2} + \frac{5}{2}

1 - \frac{144}{169}

What are the solutions to the equation 3x^2+12x-63=0 ?
The solutions to the equation 3x^2+12x-63=0 are x=3,x=-7
Find the zeros of 3x^2+12x-63=0
The zeros of 3x^2+12x-63=0 are x=3,x=-7