What is (-16-2i)/(-9+7i) ?

The solution to (-16-2i)/(-9+7i) is 1+i

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simplify (-16-2i)/(-9+7i)

simplify

\frac{- 16 - 2 i}{- 9 + 7 i}

1 + i

Solution steps

\frac{- 16 - 2 i}{- 9 + 7 i}

Multiply by the conjugate

\frac{- 9 - 7 i}{- 9 - 7 i}

= \frac{( - 16 - 2 i ) ( - 9 - 7 i )}{( - 9 + 7 i ) ( - 9 - 7 i )}

Simplify

\frac{( - 16 - 2 i ) ( - 9 - 7 i )}{( - 9 + 7 i ) ( - 9 - 7 i )} : \frac{130 + 130 i}{130}

= \frac{130 + 130 i}{130}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{130}{130} + \frac{130}{130} i

Simplify

\frac{130}{130} + \frac{130}{130} i : 1 + i

= 1 + i

(k + 1)^{3} - (k + 1)

(2 x + 5)^{4}

\frac{x}{2} + \frac{x}{4}

(- 7)^{5}

(t - 2)^{4}