What is (x^2-4)/(4x^2-8x) ?

The solution to (x^2-4)/(4x^2-8x) is (x+2)/(4x)

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simplify (x^2-4)/(4x^2-8x)

simplify

\frac{x ^{2} - 4}{4 x ^{2} - 8 x}

\frac{x + 2}{4 x}

Solution steps

\frac{x ^{2} - 4}{4 x ^{2} - 8 x}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 2 )}{4 x ^{2} - 8 x}

Factor

4 x^{2} - 8 x : 4 x (x - 2)

= \frac{( x + 2 ) ( x - 2 )}{4 x ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{x + 2}{4 x}

2 x (2 x + 1)

(a^{- 1} \cdot a^{- 2})^{- 3}

lo g_{9} (6)

\frac{8 !}{( 8 - 2 ) !}

e^{π} - e^{- π}