What is ((2x^3y^2)^3)/((3xy)^2) ?

The solution to ((2x^3y^2)^3)/((3xy)^2) is (8x^7y^4)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2x^3y^2)^3)/((3xy)^2)

simplify

\frac{( 2 x ^{3} y ^{2} ) ^{3}}{( 3 x y ) ^{2}}

\frac{8 x ^{7} y ^{4}}{9}

Solution steps

\frac{( 2 x ^{3} y ^{2} ) ^{3}}{( 3 x y ) ^{2}}

Simplify

(2 x^{3} y^{2})^{3} : 8 x^{9} y^{6}

= \frac{8 x ^{9} y ^{6}}{( 3 x y ) ^{2}}

Simplify

(3 x y)^{2} : 9 x^{2} y^{2}

= \frac{8 x ^{9} y ^{6}}{9 x ^{2} y ^{2}}

Simplify

\frac{x ^{9}}{x ^{2}} : x^{7}

= \frac{8 x ^{7} y ^{6}}{9 y ^{2}}

Simplify

\frac{y ^{6}}{y ^{2}} : y^{4}

= \frac{8 x ^{7} y ^{4}}{9}

\frac{1}{lo g _{2} ( 6 )} + \frac{1}{lo g _{108} ( 6 )}

\frac{3}{x + 1} + \frac{4}{x}

\frac{sec ( x )}{cos ( x )} - \frac{tan ( x )}{cot ( x )}

\frac{- 7 + 19 i}{4 - 5 i}

What is ((2x^3y^2)^3)/((3xy)^2) ?
The solution to ((2x^3y^2)^3)/((3xy)^2) is (8x^7y^4)/9