What is (8x)/(x^2-1)-2/(x-1) ?

The solution to (8x)/(x^2-1)-2/(x-1) is (6x-2)/((x+1)(x-1))

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simplify (8x)/(x^2-1)-2/(x-1)

simplify

\frac{8 x}{x ^{2} - 1} - \frac{2}{x - 1}

\frac{6 x - 2}{( x + 1 ) ( x - 1 )}

Solution steps

\frac{8 x}{x ^{2} - 1} - \frac{2}{x - 1}

Least Common Multiplier of

x^{2} - 1, x - 1 : (x + 1) (x - 1)

Adjust Fractions based on the LCM

= \frac{8 x}{( x + 1 ) ( x - 1 )} - \frac{2 ( x + 1 )}{( x + 1 ) ( x - 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{8 x - 2 ( x + 1 )}{( x + 1 ) ( x - 1 )}

Simplify

8 x - 2 (x + 1) : 6 x - 2

= \frac{6 x - 2}{( x + 1 ) ( x - 1 )}

\frac{3 x ^{2}}{3}

f^{- 1} (2)

\frac{3}{m - 1} + \frac{m}{1 - m}

- 9 - (- 9)

(6 t^{2})^{2}

What is (8x)/(x^2-1)-2/(x-1) ?
The solution to (8x)/(x^2-1)-2/(x-1) is (6x-2)/((x+1)(x-1))