What is expand (3x+2)(2x^2+6x-3) ?

The solution to expand (3x+2)(2x^2+6x-3) is 6x^3+22x^2+3x-6

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expand (3x+2)(2x^2+6x-3)

expand

(3 x + 2) (2 x^{2} + 6 x - 3)

6 x^{3} + 22 x^{2} + 3 x - 6

Solution steps

(3 x + 2) (2 x^{2} + 6 x - 3)

Distribute parentheses

= 3 x \cdot 2 x^{2} + 3 x \cdot 6 x + 3 x (- 3) + 2 \cdot 2 x^{2} + 2 \cdot 6 x + 2 (- 3)

Simplify

3 x \cdot 2 x^{2} + 3 x \cdot 6 x + 3 x (- 3) + 2 \cdot 2 x^{2} + 2 \cdot 6 x + 2 (- 3) : 6 x^{3} + 22 x^{2} + 3 x - 6

= 6 x^{3} + 22 x^{2} + 3 x - 6

6 x \cdot x

\frac{6 x + 4}{2 x - 3} + \frac{3 x - 9}{2 x - 3}

2 x^{3} - 3 x

196 x^{2} y^{4} - 225 z^{12}

\frac{2}{2} - \frac{2}{2}

What is expand (3x+2)(2x^2+6x-3) ?
The solution to expand (3x+2)(2x^2+6x-3) is 6x^3+22x^2+3x-6