What is (x^2+5x-6)/(x^2-9x+8)*(x^2)/(3x+18) ?

The solution to (x^2+5x-6)/(x^2-9x+8)*(x^2)/(3x+18) is (x^2)/(3(x-8))

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simplify (x^2+5x-6)/(x^2-9x+8)*(x^2)/(3x+18)

simplify

\frac{x ^{2} + 5 x - 6}{x ^{2} - 9 x + 8} \cdot \frac{x ^{2}}{3 x + 18}

\frac{x ^{2}}{3 ( x - 8 )}

Solution steps

\frac{x ^{2} + 5 x - 6}{x ^{2} - 9 x + 8} \cdot \frac{x ^{2}}{3 x + 18}

Cancel

\frac{x ^{2} + 5 x - 6}{x ^{2} - 9 x + 8} : \frac{x + 6}{x - 8}

= \frac{x + 6}{x - 8} \cdot \frac{x ^{2}}{3 x + 18}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x + 6 ) x ^{2}}{( x - 8 ) ( 3 x + 18 )}

Factor

3 x + 18 : 3 (x + 6)

= \frac{( x + 6 ) x ^{2}}{( x - 8 ) \cdot 3 ( x + 6 )}

Cancel the common factor:

x + 6

= \frac{x ^{2}}{( x - 8 ) \cdot 3}

= \frac{x ^{2}}{3 ( x - 8 )}

25 x^{4}

(6 m n^{4} + 3 m^{5} p)^{2}

\frac{1}{\frac{x}{x}}

cot (θ) (\frac{1}{3 cos ( θ )} + \frac{2}{cot ( θ )} - tan (θ))

3.14 \cdot 7^{2}

What is (x^2+5x-6)/(x^2-9x+8)*(x^2)/(3x+18) ?
The solution to (x^2+5x-6)/(x^2-9x+8)*(x^2)/(3x+18) is (x^2)/(3(x-8))