What is (\frac{-4x-12)/(x-7)}{(x^2-12x+36)/(2x-14)} ?

The solution to (\frac{-4x-12)/(x-7)}{(x^2-12x+36)/(2x-14)} is (2(-4x-12))/(x^2-12x+36)

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simplify (\frac{-4x-12)/(x-7)}{(x^2-12x+36)/(2x-14)}

simplify

\frac{\frac{- 4 x - 12}{x - 7}}{\frac{x ^{2} - 12 x + 36}{2 x - 14}}

\frac{2 ( - 4 x - 12 )}{x ^{2} - 12 x + 36}

Solution steps

\frac{\frac{- 4 x - 12}{x - 7}}{\frac{x ^{2} - 12 x + 36}{2 x - 14}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( - 4 x - 12 ) ( 2 x - 14 )}{( x - 7 ) ( x ^{2} - 12 x + 36 )}

Cancel

\frac{( - 4 x - 12 ) ( 2 x - 14 )}{( x - 7 ) ( x ^{2} - 12 x + 36 )} : \frac{( - 4 x - 12 ) \cdot 2}{x ^{2} - 12 x + 36}

= \frac{( - 4 x - 12 ) \cdot 2}{x ^{2} - 12 x + 36}

= \frac{2 ( - 4 x - 12 )}{x ^{2} - 12 x + 36}

lo g_{6} (\frac{1}{6})

2 - 12 x

5^{2 x}

\frac{1}{25} x^{4} - \frac{9}{16} y^{4}

(x^{3} + 4)^{2} + ln ((2 x)^{x})

What is (\frac{-4x-12)/(x-7)}{(x^2-12x+36)/(2x-14)} ?
The solution to (\frac{-4x-12)/(x-7)}{(x^2-12x+36)/(2x-14)} is (2(-4x-12))/(x^2-12x+36)