What is (\frac{x^2-6x+9)/(4x^2-1)}{(x^2+5x-24)/(2x^2+17x+8)} ?

The solution to (\frac{x^2-6x+9)/(4x^2-1)}{(x^2+5x-24)/(2x^2+17x+8)} is (x-3)/(2x-1)

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simplify (\frac{x^2-6x+9)/(4x^2-1)}{(x^2+5x-24)/(2x^2+17x+8)}

simplify

\frac{\frac{x ^{2} - 6 x + 9}{4 x ^{2} - 1}}{\frac{x ^{2} + 5 x - 24}{2 x ^{2} + 17 x + 8}}

\frac{x - 3}{2 x - 1}

Solution steps

\frac{\frac{x ^{2} - 6 x + 9}{4 x ^{2} - 1}}{\frac{x ^{2} + 5 x - 24}{2 x ^{2} + 17 x + 8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 6 x + 9 ) ( 2 x ^{2} + 17 x + 8 )}{( 4 x ^{2} - 1 ) ( x ^{2} + 5 x - 24 )}

Cancel

\frac{( x ^{2} - 6 x + 9 ) ( 2 x ^{2} + 17 x + 8 )}{( 4 x ^{2} - 1 ) ( x ^{2} + 5 x - 24 )} : \frac{x - 3}{2 x - 1}

= \frac{x - 3}{2 x - 1}

2 \frac{5}{6}

\frac{1}{- 8}

(\frac{i}{1 + i})^{- 1}

2 x \times 2

What is (\frac{x^2-6x+9)/(4x^2-1)}{(x^2+5x-24)/(2x^2+17x+8)} ?
The solution to (\frac{x^2-6x+9)/(4x^2-1)}{(x^2+5x-24)/(2x^2+17x+8)} is (x-3)/(2x-1)