What is (2x^2-8x)/(x-4)*(x+2)/(8x) ?

The solution to (2x^2-8x)/(x-4)*(x+2)/(8x) is (x+2)/4

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simplify (2x^2-8x)/(x-4)*(x+2)/(8x)

simplify

\frac{2 x ^{2} - 8 x}{x - 4} \cdot \frac{x + 2}{8 x}

\frac{x + 2}{4}

Solution steps

\frac{2 x ^{2} - 8 x}{x - 4} \cdot \frac{x + 2}{8 x}

Cancel

\frac{2 x ^{2} - 8 x}{x - 4} : 2 x

= 2 x \frac{x + 2}{8 x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 x ( x + 2 )}{8 x}

Cancel the common factor:

x

= \frac{2 ( x + 2 )}{8}

Factor the number:

8 = 2 \cdot 4

= \frac{2 ( x + 2 )}{2 \cdot 4}

Cancel the common factor:

2

= \frac{x + 2}{4}

9 + 12

\frac{x + a}{x + 3 a} + \frac{3 a ^{2} - x ^{2}}{x ^{2} - 9 a ^{2}}

\frac{56}{63}

9 x + 3

(4 i) (- 3 i)

What is (2x^2-8x)/(x-4)*(x+2)/(8x) ?
The solution to (2x^2-8x)/(x-4)*(x+2)/(8x) is (x+2)/4