What is (\frac{x^2)/(x^2+7x+6)}{(9x-9)/(x^2-1)} ?

The solution to (\frac{x^2)/(x^2+7x+6)}{(9x-9)/(x^2-1)} is (x^2)/(9(x+6))

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simplify (\frac{x^2)/(x^2+7x+6)}{(9x-9)/(x^2-1)}

simplify

\frac{\frac{x ^{2}}{x ^{2} + 7 x + 6}}{\frac{9 x - 9}{x ^{2} - 1}}

\frac{x ^{2}}{9 ( x + 6 )}

Solution steps

\frac{\frac{x ^{2}}{x ^{2} + 7 x + 6}}{\frac{9 x - 9}{x ^{2} - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{x ^{2} ( x ^{2} - 1 )}{( x ^{2} + 7 x + 6 ) ( 9 x - 9 )}

Cancel

\frac{x ^{2} ( x ^{2} - 1 )}{( x ^{2} + 7 x + 6 ) ( 9 x - 9 )} : \frac{x ^{2}}{( x + 6 ) \cdot 9}

= \frac{x ^{2}}{( x + 6 ) \cdot 9}

= \frac{x ^{2}}{9 ( x + 6 )}

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f (x) = x^{4} - 2

(x + 2) (x + 4) (x + 6)

What is (\frac{x^2)/(x^2+7x+6)}{(9x-9)/(x^2-1)} ?
The solution to (\frac{x^2)/(x^2+7x+6)}{(9x-9)/(x^2-1)} is (x^2)/(9(x+6))