What is expand 3x^2*(2x^3-3x^2+4x-2) ?

The solution to expand 3x^2*(2x^3-3x^2+4x-2) is 6x^5-9x^4+12x^3-6x^2

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expand 3x^2*(2x^3-3x^2+4x-2)

expand

3 x^{2} \cdot (2 x^{3} - 3 x^{2} + 4 x - 2)

6 x^{5} - 9 x^{4} + 12 x^{3} - 6 x^{2}

Solution steps

3 x^{2} (2 x^{3} - 3 x^{2} + 4 x - 2)

Distribute parentheses

= 3 x^{2} \cdot 2 x^{3} + 3 x^{2} (- 3 x^{2}) + 3 x^{2} \cdot 4 x + 3 x^{2} (- 2)

Simplify

3 x^{2} \cdot 2 x^{3} + 3 x^{2} (- 3 x^{2}) + 3 x^{2} \cdot 4 x + 3 x^{2} (- 2) : 6 x^{5} - 9 x^{4} + 12 x^{3} - 6 x^{2}

= 6 x^{5} - 9 x^{4} + 12 x^{3} - 6 x^{2}

(3 x - 3) (x - 4)

\frac{3}{2 x}

(a^{6} + 7) (a^{6} - 9)

lo g_{5} (40)

\frac{6 x}{3}

What is expand 3x^2*(2x^3-3x^2+4x-2) ?
The solution to expand 3x^2*(2x^3-3x^2+4x-2) is 6x^5-9x^4+12x^3-6x^2