What is ((x^2-2x-3)/(x^3)}{\frac{x^2-6x-7)/x} ?

The solution to ((x^2-2x-3)/(x^3)}{\frac{x^2-6x-7)/x} is (x-3)/(x^2(x-7))

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simplify ((x^2-2x-3)/(x^3)}{\frac{x^2-6x-7)/x}

simplify

\frac{\frac{x ^{2} - 2 x - 3}{x ^{3}}}{\frac{x ^{2} - 6 x - 7}{x}}

\frac{x - 3}{x ^{2} ( x - 7 )}

Solution steps

\frac{\frac{x ^{2} - 2 x - 3}{x ^{3}}}{\frac{x ^{2} - 6 x - 7}{x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 2 x - 3 ) x}{x ^{3} ( x ^{2} - 6 x - 7 )}

Cancel

\frac{( x ^{2} - 2 x - 3 ) x}{x ^{3} ( x ^{2} - 6 x - 7 )} : \frac{x - 3}{x ^{2} ( x - 7 )}

= \frac{x - 3}{x ^{2} ( x - 7 )}

\frac{\frac{x - 2}{x - 1}}{\frac{x ^{2} - 4}{x ^{2} + x - 2}}

x (x + 1) (x + 2) (x + 3) + 1

\frac{3}{8} \cdot \frac{1}{2}

(13 + - 180) (6 + - 180)

(3 cos (t))^{2}

What is ((x^2-2x-3)/(x^3)}{\frac{x^2-6x-7)/x} ?
The solution to ((x^2-2x-3)/(x^3)}{\frac{x^2-6x-7)/x} is (x-3)/(x^2(x-7))