What is expand (x-3)(x-4)(x-5) ?

The solution to expand (x-3)(x-4)(x-5) is x^3-12x^2+47x-60

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expand (x-3)(x-4)(x-5)

expand

(x - 3) (x - 4) (x - 5)

x^{3} - 12 x^{2} + 47 x - 60

Solution steps

(x - 3) (x - 4) (x - 5)

Expand

(x - 3) (x - 4) (x - 5) : (x^{2} - 7 x + 12) (x - 5)

= (x^{2} - 7 x + 12) (x - 5)

Distribute parentheses

= x^{2} x + x^{2} (- 5) - 7 xx - 7 x (- 5) + 12 x + 12 (- 5)

Simplify

x^{2} x + x^{2} (- 5) - 7 xx - 7 x (- 5) + 12 x + 12 (- 5) : x^{3} - 12 x^{2} + 47 x - 60

= x^{3} - 12 x^{2} + 47 x - 60

\frac{ln ( 9 )}{2}

6.2 + 8.9 w - 12 - 11.2 w - 6.2

8 \times \frac{1}{4}

\frac{e}{ln ( e )}

(- (- 0.5 a c^{2})^{2})^{3}

What is expand (x-3)(x-4)(x-5) ?
The solution to expand (x-3)(x-4)(x-5) is x^3-12x^2+47x-60