What is (2x-10)/(x+8)*(x^2-64)/(x^2+3x-40) ?

The solution to (2x-10)/(x+8)*(x^2-64)/(x^2+3x-40) is (2(x-8))/(x+8)

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simplify (2x-10)/(x+8)*(x^2-64)/(x^2+3x-40)

simplify

\frac{2 x - 10}{x + 8} \cdot \frac{x ^{2} - 64}{x ^{2} + 3 x - 40}

\frac{2 ( x - 8 )}{x + 8}

Solution steps

\frac{2 x - 10}{x + 8} \cdot \frac{x ^{2} - 64}{x ^{2} + 3 x - 40}

Cancel

\frac{x ^{2} - 64}{x ^{2} + 3 x - 40} : \frac{x - 8}{x - 5}

= \frac{2 x - 10}{x + 8} \cdot \frac{x - 8}{x - 5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 2 x - 10 ) ( x - 8 )}{( x + 8 ) ( x - 5 )}

Factor

2 x - 10 : 2 (x - 5)

= \frac{2 ( x - 5 ) ( x - 8 )}{( x + 8 ) ( x - 5 )}

Cancel the common factor:

x - 5

= \frac{2 ( x - 8 )}{x + 8}

- x (x)

x^{2} + 1^{2}

\frac{3}{- 1}

5 x - 4 x^{2}

sin^{2} (x) + sin^{2} (x)

What is (2x-10)/(x+8)*(x^2-64)/(x^2+3x-40) ?
The solution to (2x-10)/(x+8)*(x^2-64)/(x^2+3x-40) is (2(x-8))/(x+8)