What are the solutions to the equation u^2-u-6=0 ?

The solutions to the equation u^2-u-6=0 are u=3,u=-2

Find the zeros of u^2-u-6=0

The zeros of u^2-u-6=0 are u=3,u=-2

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u^{2} - u - 6 = 0

u = 3, u = - 2

Solution steps

u^{2} - u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

u_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, u_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

u = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

u = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

u = 3, u = - 2

3 x + 7 - x - 2 > 9

4 x + 5 \leq 5

(x - 2)^{4} + 10 (x - 2)^{2} + 9

2 x^{2} + 6 x + 18

5 x^{2} + 3 x + 9 = - 10 x + 3

What are the solutions to the equation u^2-u-6=0 ?
The solutions to the equation u^2-u-6=0 are u=3,u=-2
Find the zeros of u^2-u-6=0
The zeros of u^2-u-6=0 are u=3,u=-2