What is expand (2x^2-3)(2x^3-3x^2+4x) ?

The solution to expand (2x^2-3)(2x^3-3x^2+4x) is 4x^5-6x^4+2x^3+9x^2-12x

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expand (2x^2-3)(2x^3-3x^2+4x)

expand

(2 x^{2} - 3) (2 x^{3} - 3 x^{2} + 4 x)

4 x^{5} - 6 x^{4} + 2 x^{3} + 9 x^{2} - 12 x

Solution steps

(2 x^{2} - 3) (2 x^{3} - 3 x^{2} + 4 x)

Distribute parentheses

= 2 x^{2} \cdot 2 x^{3} + 2 x^{2} (- 3 x^{2}) + 2 x^{2} \cdot 4 x - 3 \cdot 2 x^{3} - 3 (- 3 x^{2}) - 3 \cdot 4 x

Simplify

2 x^{2} \cdot 2 x^{3} + 2 x^{2} (- 3 x^{2}) + 2 x^{2} \cdot 4 x - 3 \cdot 2 x^{3} - 3 (- 3 x^{2}) - 3 \cdot 4 x : 4 x^{5} - 6 x^{4} + 2 x^{3} + 9 x^{2} - 12 x

= 4 x^{5} - 6 x^{4} + 2 x^{3} + 9 x^{2} - 12 x

\frac{43}{2}

(2 - 2)^{2}

\frac{- 108 a ^{7} b ^{6} c ^{8}}{- 20 b ^{6} c ^{8}}

(2 - 49) (- 36)

(3 x - 5) (x - 1)^{2}

What is expand (2x^2-3)(2x^3-3x^2+4x) ?
The solution to expand (2x^2-3)(2x^3-3x^2+4x) is 4x^5-6x^4+2x^3+9x^2-12x