What is expand (x+2)(x-1)(x-4) ?

The solution to expand (x+2)(x-1)(x-4) is x^3-3x^2-6x+8

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expand (x+2)(x-1)(x-4)

expand

(x + 2) (x - 1) (x - 4)

x^{3} - 3 x^{2} - 6 x + 8

Solution steps

(x + 2) (x - 1) (x - 4)

Expand

(x + 2) (x - 1) (x - 4) : (x^{2} + x - 2) (x - 4)

= (x^{2} + x - 2) (x - 4)

Distribute parentheses

= x^{2} x + x^{2} (- 4) + xx + x (- 4) - 2 x - 2 (- 4)

Simplify

x^{2} x + x^{2} (- 4) + xx + x (- 4) - 2 x - 2 (- 4) : x^{3} - 3 x^{2} - 6 x + 8

= x^{3} - 3 x^{2} - 6 x + 8

\frac{75}{180}

b - 3 + 6 - 2 b

(x + y) - (x - y)

\frac{2 7 + 14}{7}

What is expand (x+2)(x-1)(x-4) ?
The solution to expand (x+2)(x-1)(x-4) is x^3-3x^2-6x+8