What is (\frac{x^2-81)/(x^2-x-72)}{(x-2)/(x+8)} ?

The solution to (\frac{x^2-81)/(x^2-x-72)}{(x-2)/(x+8)} is (x+9)/(x-2)

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simplify (\frac{x^2-81)/(x^2-x-72)}{(x-2)/(x+8)}

simplify

\frac{\frac{x ^{2} - 81}{x ^{2} - x - 72}}{\frac{x - 2}{x + 8}}

\frac{x + 9}{x - 2}

Solution steps

\frac{\frac{x ^{2} - 81}{x ^{2} - x - 72}}{\frac{x - 2}{x + 8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 81 ) ( x + 8 )}{( x ^{2} - x - 72 ) ( x - 2 )}

Cancel

\frac{( x ^{2} - 81 ) ( x + 8 )}{( x ^{2} - x - 72 ) ( x - 2 )} : \frac{x + 9}{x - 2}

= \frac{x + 9}{x - 2}

6 y (2 - y)

(3 x + 2 y) (3 x - y)

\frac{20 3}{3}

2 (- 14 + r) - (- 3 r - 5)

\frac{1}{6} 0.0144 + \frac{1}{3} 729

What is (\frac{x^2-81)/(x^2-x-72)}{(x-2)/(x+8)} ?
The solution to (\frac{x^2-81)/(x^2-x-72)}{(x-2)/(x+8)} is (x+9)/(x-2)