What are the solutions to the equation x^2-3x=x-1 ?

The solutions to the equation x^2-3x=x-1 are x=2+sqrt(3),x=2-sqrt(3)

Find the zeros of x^2-3x=x-1

The zeros of x^2-3x=x-1 are x=2+sqrt(3),x=2-sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x = x - 1

x = 2 + 3, x = 2 - 3

Solution steps

x^{2} - 3 x = x - 1

Move

1

to the left side

x^{2} - 3 x + 1 = x

Move

x

to the left side

x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 1 = 23

x_{1, 2} = \frac{- ( - 4 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 3}{2 \cdot 1} : 2 + 3

x = \frac{- ( - 4 ) - 2 3}{2 \cdot 1} : 2 - 3

The solutions to the quadratic equation are:

x = 2 + 3, x = 2 - 3

1 - 0.6 L + 0.08 L^{2} = 0

40 = 4 t^{2} + 12 t

- 32 c \leq 0

6 x^{2} = 375

\frac{5 a ^{- 5} b ^{4}}{15 a ^{2} b ^{- 6}}

What are the solutions to the equation x^2-3x=x-1 ?
The solutions to the equation x^2-3x=x-1 are x=2+sqrt(3),x=2-sqrt(3)
Find the zeros of x^2-3x=x-1
The zeros of x^2-3x=x-1 are x=2+sqrt(3),x=2-sqrt(3)