What is (3c^4+6c^3-2c+4)(c+2)^{-1} ?

The solution to (3c^4+6c^3-2c+4)(c+2)^{-1} is (3c^4+6c^3-2c+4)/(c+2)

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simplify (3c^4+6c^3-2c+4)(c+2)^{-1}

simplify

(3 c^{4} + 6 c^{3} - 2 c + 4) (c + 2)^{- 1}

\frac{3 c ^{4} + 6 c ^{3} - 2 c + 4}{c + 2}

Solution steps

(3 c^{4} + 6 c^{3} - 2 c + 4) (c + 2)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(c + 2)^{- 1} = \frac{1}{c + 2}

= (3 c^{4} + 6 c^{3} - 2 c + 4) \frac{1}{c + 2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 c ^{4} + 6 c ^{3} - 2 c + 4 ) \cdot 1}{c + 2}

Apply rule:

a \cdot 1 = a

(3 c^{4} + 6 c^{3} - 2 c + 4) \cdot 1 = (3 c^{4} + 6 c^{3} - 2 c + 4)

= \frac{3 c ^{4} + 6 c ^{3} - 2 c + 4}{c + 2}

\frac{2 x ^{2}}{x ^{3}}

x \cdot x \cdot x

(2 m n^{3} + 7) (2 m n^{3} - 7)

3^{2} x 3^{2}

- 2 (4)

What is (3c^4+6c^3-2c+4)(c+2)^{-1} ?
The solution to (3c^4+6c^3-2c+4)(c+2)^{-1} is (3c^4+6c^3-2c+4)/(c+2)