What is (\frac{x^2)/(3y^2)}{(2x)/(y^3)} ?

The solution to (\frac{x^2)/(3y^2)}{(2x)/(y^3)} is (xy)/6

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simplify (\frac{x^2)/(3y^2)}{(2x)/(y^3)}

simplify

\frac{\frac{x ^{2}}{3 y ^{2}}}{\frac{2 x}{y ^{3}}}

\frac{x y}{6}

Solution steps

\frac{\frac{x ^{2}}{3 y ^{2}}}{\frac{2 x}{y ^{3}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{x ^{2} y ^{3}}{3 y ^{2} \cdot 2 x}

Cancel

\frac{x ^{2} y ^{3}}{3 y ^{2} \cdot 2 x} : \frac{x y}{6}

= \frac{x y}{6}

4^{2} + 1^{2}

10 \div \frac{2}{5}

\frac{( 8 x ^{3} + 27 )}{( 2 x + 3 )}

\frac{1}{4} \times \frac{3}{4}

100 x^{4} - 30 x^{2}

What is (\frac{x^2)/(3y^2)}{(2x)/(y^3)} ?
The solution to (\frac{x^2)/(3y^2)}{(2x)/(y^3)} is (xy)/6