What is (12^7*30^5)/(25^2*8^5*27^4) ?

The solution to (12^7*30^5)/(25^2*8^5*27^4) is 80

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (12^730^5)/(25^28^5*27^4)

simplify

\frac{1 2 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 8 ^{5} \cdot 2 7 ^{4}}

80

Solution steps

\frac{1 2 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 8 ^{5} \cdot 2 7 ^{4}}

Factor

1 2^{7} : 4^{7} \cdot 3^{7}

= \frac{4 ^{7} \cdot 3 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 8 ^{5} \cdot 2 7 ^{4}}

Factor

8^{5} : 4^{5} \cdot 2^{5}

= \frac{4 ^{7} \cdot 3 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 4 ^{5} \cdot 2 ^{5} \cdot 2 7 ^{4}}

\frac{4 ^{7}}{4 ^{5}} = 4^{2}

= \frac{4 ^{2} \cdot 3 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 2 ^{5} \cdot 2 7 ^{4}}

Factor

4^{2} : 2^{4}

= \frac{2 ^{4} \cdot 3 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 2 ^{5} \cdot 2 7 ^{4}}

\frac{2 ^{4}}{2 ^{5}} = \frac{1}{2}

= \frac{3 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 2 \cdot 2 7 ^{4}}

Factor

2 7^{4} : 3^{12}

= \frac{3 ^{7} \cdot 3 0 ^{5}}{2 5 ^{2} \cdot 2 \cdot 3 ^{12}}

\frac{3 ^{7}}{3 ^{12}} = \frac{1}{3 ^{5}}

= \frac{3 0 ^{5}}{2 5 ^{2} \cdot 2 \cdot 3 ^{5}}

Factor

3 0^{5} : 5^{5} \cdot 6^{5}

= \frac{5 ^{5} \cdot 6 ^{5}}{2 5 ^{2} \cdot 2 \cdot 3 ^{5}}

Factor

2 5^{2} : 5^{4}

= \frac{5 ^{5} \cdot 6 ^{5}}{5 ^{4} \cdot 2 \cdot 3 ^{5}}

\frac{5 ^{5}}{5 ^{4}} = 5

= \frac{5 \cdot 6 ^{5}}{2 \cdot 3 ^{5}}

Factor

6^{5} : 2^{5} \cdot 3^{5}

= \frac{5 \cdot 2 ^{5} \cdot 3 ^{5}}{2 \cdot 3 ^{5}}

\frac{2 ^{5}}{2} = 2^{4}

= \frac{5 \cdot 2 ^{4} \cdot 3 ^{5}}{3 ^{5}}

Cancel the common factor:

3^{5}

= 5 \cdot 2^{4}

5 \cdot 2^{4} = 80

= 80

(4^{- 1})^{- 3}

- 4 (- 3)

- 6 (x + 2) - 2

(x^{2} - 4 x + 2) (- x^{2} - 4 x - 4)

\frac{\frac{1}{x}}{- \frac{1}{x ^{2}}}

What is (12^7*30^5)/(25^2*8^5*27^4) ?
The solution to (12^7*30^5)/(25^2*8^5*27^4) is 80