What is a^2+b^2+2ab-(a^2+b^2-2ab)-4ab ?

The solution to a^2+b^2+2ab-(a^2+b^2-2ab)-4ab is 0

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simplify a^2+b^2+2ab-(a^2+b^2-2ab)-4ab

simplify

a^{2} + b^{2} + 2 ab - (a^{2} + b^{2} - 2 ab) - 4 ab

0

Solution steps

a^{2} + b^{2} + 2 ab - (a^{2} + b^{2} - 2 ab) - 4 ab

Group like terms

= - (a^{2} + b^{2} - 2 ab) + a^{2} + b^{2} + 2 ab - 4 ab

Add similar elements:

2 ab - 4 ab = - 2 ab

= - (a^{2} + b^{2} - 2 ab) + a^{2} + b^{2} - 2 ab

Apply the distributive law:

- (a + b) = - a - b

- (a^{2} + b^{2} - 2 ab) = - a^{2} - b^{2} + 2 ab

= - a^{2} - b^{2} + 2 ab + a^{2} + b^{2} - 2 ab

Group like terms

= - a^{2} + a^{2} - b^{2} + b^{2} + 2 ab - 2 ab

Add similar elements:

- a^{2} + a^{2} = 0

= - b^{2} + b^{2} + 2 ab - 2 ab

Add similar elements:

- b^{2} + b^{2} = 0

= 2 ab - 2 ab

Add similar elements:

2 ab - 2 ab = 0

= 0

(a - 7)^{2}

50 \cdot 5

\frac{8 !}{6 ! ( 8 - 6 ) !}

\frac{150}{5 + 25 e ^{- 0.45 (3)}}

- x^{2} - 2

What is a^2+b^2+2ab-(a^2+b^2-2ab)-4ab ?
The solution to a^2+b^2+2ab-(a^2+b^2-2ab)-4ab is 0