What is (\frac{2a+2b)/(a^2+ab)}{4/a} ?

The solution to (\frac{2a+2b)/(a^2+ab)}{4/a} is 1/2

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simplify (\frac{2a+2b)/(a^2+ab)}{4/a}

simplify

\frac{\frac{2 a + 2 b}{a ^{2} + ab}}{\frac{4}{a}}

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\frac{\frac{2 a + 2 b}{a ^{2} + ab}}{\frac{4}{a}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 2 a + 2 b ) a}{( a ^{2} + ab ) \cdot 4}

Cancel

\frac{( 2 a + 2 b ) a}{( a ^{2} + ab ) \cdot 4} : \frac{1}{2}

= \frac{1}{2}

5 \cdot 4 \cdot 3 \cdot 2

(3 x - 2) (x^{2} - 2 x + 1)

24 - 3 x

(x^{2} - 1)^{3}

5 (x - 1)

What is (\frac{2a+2b)/(a^2+ab)}{4/a} ?
The solution to (\frac{2a+2b)/(a^2+ab)}{4/a} is 1/2