What is (\frac{x^2-1)/(2x+2)}{(x^2-6x+5)/(2x^2)} ?

The solution to (\frac{x^2-1)/(2x+2)}{(x^2-6x+5)/(2x^2)} is (x^2)/(x-5)

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simplify (\frac{x^2-1)/(2x+2)}{(x^2-6x+5)/(2x^2)}

simplify

\frac{\frac{x ^{2} - 1}{2 x + 2}}{\frac{x ^{2} - 6 x + 5}{2 x ^{2}}}

\frac{x ^{2}}{x - 5}

Solution steps

\frac{\frac{x ^{2} - 1}{2 x + 2}}{\frac{x ^{2} - 6 x + 5}{2 x ^{2}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 1 ) \cdot 2 x ^{2}}{( 2 x + 2 ) ( x ^{2} - 6 x + 5 )}

Cancel

\frac{( x ^{2} - 1 ) \cdot 2 x ^{2}}{( 2 x + 2 ) ( x ^{2} - 6 x + 5 )} : \frac{x ^{2}}{x - 5}

= \frac{x ^{2}}{x - 5}

2 \times \frac{1}{2}

\frac{3}{5} \div 3

\frac{5 v ^{2} - 5 v}{1 - v}

2 (\frac{x}{2})

20 \cdot 2

What is (\frac{x^2-1)/(2x+2)}{(x^2-6x+5)/(2x^2)} ?
The solution to (\frac{x^2-1)/(2x+2)}{(x^2-6x+5)/(2x^2)} is (x^2)/(x-5)