What is 7x+4^2-[10^2+5(2x-3)+7(2x-1)] ?

The solution to 7x+4^2-[10^2+5(2x-3)+7(2x-1)] is -17x-62

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simplify 7x+4^2-[10^2+5(2x-3)+7(2x-1)]

simplify

7 x + 4^{2} - [1 0^{2} + 5 (2 x - 3) + 7 (2 x - 1)]

- 17 x - 62

Solution steps

7 x + 4^{2} - (1 0^{2} + 5 (2 x - 3) + 7 (2 x - 1))

4^{2} = 16

- (1 0^{2} + 5 (2 x - 3) + 7 (2 x - 1)) = - 24 x - 78

= 7 x + 16 - 24 x - 78

Group like terms

= 7 x - 24 x + 16 - 78

Add similar elements:

7 x - 24 x = - 17 x

= - 17 x + 16 - 78

Subtract the numbers:

16 - 78 = - 62

= - 17 x - 62

- 225

\frac{30}{42}

\frac{2 x + 3}{x - 8} + \frac{3 x + 7}{x - 1}

4 x + 5 x

4 x + 4 x

What is 7x+4^2-[10^2+5(2x-3)+7(2x-1)] ?
The solution to 7x+4^2-[10^2+5(2x-3)+7(2x-1)] is -17x-62