What is ((5x^5y^3z^{-2})/(10xy^5z^4))^{-2} ?

The solution to ((5x^5y^3z^{-2})/(10xy^5z^4))^{-2} is (4y^4z^{12})/(x^8)

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simplify ((5x^5y^3z^{-2})/(10xy^5z^4))^{-2}

simplify

(\frac{5 x ^{5} y ^{3} z ^{- 2}}{10 x y ^{5} z ^{4}})^{- 2}

\frac{4 y ^{4} z ^{12}}{x ^{8}}

Solution steps

(\frac{5 x ^{5} y ^{3} z ^{- 2}}{10 x y ^{5} z ^{4}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{5 x ^{5} y ^{3} z ^{- 2}}{10 x y ^{5} z ^{4}})^{- 2} = \frac{1}{( \frac{5 x ^{5} y ^{3} z ^{- 2}}{10 x y ^{5} z ^{4}} ) ^{2}}

= \frac{1}{( \frac{5 x ^{5} y ^{3} z ^{- 2}}{10 x y ^{5} z ^{4}} ) ^{2}}

Simplify

(\frac{5 x ^{5} y ^{3} z ^{- 2}}{10 x y ^{5} z ^{4}})^{2} : \frac{x ^{8}}{4 y ^{4} z ^{12}}

= \frac{1}{\frac{x ^{8}}{4 y ^{4} z ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{4 y ^{4} z ^{12}}{x ^{8}}

1 + \frac{1}{x ^{2}}

(6 + i) + (4 - 5 i)

lo g_{2} (lo g_{2} (256))

9 \cdot (- 3)

e^{0} - e^{- 0}

What is ((5x^5y^3z^{-2})/(10xy^5z^4))^{-2} ?
The solution to ((5x^5y^3z^{-2})/(10xy^5z^4))^{-2} is (4y^4z^{12})/(x^8)