What is (x^3+1)/(x^2-1) ?

The solution to (x^3+1)/(x^2-1) is (x^2-x+1)/(x-1)

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simplify (x^3+1)/(x^2-1)

simplify

\frac{x ^{3} + 1}{x ^{2} - 1}

\frac{x ^{2} - x + 1}{x - 1}

Solution steps

\frac{x ^{3} + 1}{x ^{2} - 1}

Factor

x^{3} + 1 : (x + 1) (x^{2} - x + 1)

= \frac{( x + 1 ) ( x ^{2} - x + 1 )}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x ^{2} - x + 1 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x + 1

= \frac{x ^{2} - x + 1}{x - 1}

0.24

\frac{2}{2}

\frac{2}{3} + \frac{4}{7}

\frac{2 x ^{3}}{2 x}

(2 x - 2 y)^{2}