What is (x^2+8x+16)/(x^2+3x-4) ?

The solution to (x^2+8x+16)/(x^2+3x-4) is (x+4)/(x-1)

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simplify (x^2+8x+16)/(x^2+3x-4)

simplify

\frac{x ^{2} + 8 x + 16}{x ^{2} + 3 x - 4}

\frac{x + 4}{x - 1}

Solution steps

\frac{x ^{2} + 8 x + 16}{x ^{2} + 3 x - 4}

Factor

x^{2} + 8 x + 16 : (x + 4)^{2}

= \frac{( x + 4 ) ^{2}}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x + 4 ) ^{2}}{( x - 1 ) ( x + 4 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 4)^{2} = (x + 4) (x + 4)

= \frac{( x + 4 ) ( x + 4 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x + 4}{x - 1}

\frac{7}{x} - \frac{6}{x + 3}

(3 x + 8) (3 x - 8)

(5 x - 8)^{2}

7 x^{2} - 8 x

\frac{ln ( \frac{1}{2} )}{5730}

What is (x^2+8x+16)/(x^2+3x-4) ?
The solution to (x^2+8x+16)/(x^2+3x-4) is (x+4)/(x-1)