What is (x^2-4x-5)/((x-1)^2-4(x-1)) ?

The solution to (x^2-4x-5)/((x-1)^2-4(x-1)) is (x+1)/(x-1)

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simplify (x^2-4x-5)/((x-1)^2-4(x-1))

simplify

\frac{x ^{2} - 4 x - 5}{( x - 1 ) ^{2} - 4 ( x - 1 )}

\frac{x + 1}{x - 1}

Solution steps

\frac{x ^{2} - 4 x - 5}{( x - 1 ) ^{2} - 4 ( x - 1 )}

Factor

x^{2} - 4 x - 5 : (x + 1) (x - 5)

= \frac{( x + 1 ) ( x - 5 )}{( x - 1 ) ^{2} - 4 ( x - 1 )}

Factor out common term

(x - 1) : (x - 1) (x - 5)

= \frac{( x + 1 ) ( x - 5 )}{( x - 1 ) ( x - 5 )}

Cancel the common factor:

x - 5

= \frac{x + 1}{x - 1}

\frac{1}{1 - sin ( θ )} + \frac{1}{1 + sin ( θ )}

\frac{2}{3} \div \frac{2}{3}

2 (3 + 4 y + 5)

1.5 \times 1.5

\frac{- 2}{2}

What is (x^2-4x-5)/((x-1)^2-4(x-1)) ?
The solution to (x^2-4x-5)/((x-1)^2-4(x-1)) is (x+1)/(x-1)