What is (\frac{x^2+11x+30)/(x^2-9)}{(x^2-36)/(x-3)} ?

The solution to (\frac{x^2+11x+30)/(x^2-9)}{(x^2-36)/(x-3)} is (x+5)/((x+3)(x-6))

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simplify (\frac{x^2+11x+30)/(x^2-9)}{(x^2-36)/(x-3)}

simplify

\frac{\frac{x ^{2} + 11 x + 30}{x ^{2} - 9}}{\frac{x ^{2} - 36}{x - 3}}

\frac{x + 5}{( x + 3 ) ( x - 6 )}

Solution steps

\frac{\frac{x ^{2} + 11 x + 30}{x ^{2} - 9}}{\frac{x ^{2} - 36}{x - 3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + 11 x + 30 ) ( x - 3 )}{( x ^{2} - 9 ) ( x ^{2} - 36 )}

Cancel

\frac{( x ^{2} + 11 x + 30 ) ( x - 3 )}{( x ^{2} - 9 ) ( x ^{2} - 36 )} : \frac{x + 5}{( x + 3 ) ( x - 6 )}

= \frac{x + 5}{( x + 3 ) ( x - 6 )}

\frac{x ^{8} y ^{12}}{x ^{4} y ^{15}}

x^{\frac{3}{4}} x^{- 1}

5 (- 1)

12 x^{2} - 13 x - 35

64 \times 2

What is (\frac{x^2+11x+30)/(x^2-9)}{(x^2-36)/(x-3)} ?
The solution to (\frac{x^2+11x+30)/(x^2-9)}{(x^2-36)/(x-3)} is (x+5)/((x+3)(x-6))