What are the solutions to the equation x^2-3x-28=0 ?

The solutions to the equation x^2-3x-28=0 are x=7,x=-4

Find the zeros of x^2-3x-28=0

The zeros of x^2-3x-28=0 are x=7,x=-4

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x^{2} - 3 x - 28 = 0

x = 7, x = - 4

Solution steps

x^{2} - 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 1}

x = \frac{- ( - 3 ) + 11}{2 \cdot 1} : 7

x = \frac{- ( - 3 ) - 11}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 7, x = - 4

81 \cdot 3

\frac{11}{2}

\frac{2}{5} (x - 2) = - 3

- 5 y^{2} - 8 y + 4

2 r^{2} + 4 r + 2 = 0

What are the solutions to the equation x^2-3x-28=0 ?
The solutions to the equation x^2-3x-28=0 are x=7,x=-4
Find the zeros of x^2-3x-28=0
The zeros of x^2-3x-28=0 are x=7,x=-4